[2019CCPC哈尔滨] F-Fixing Banners

题目:F-Fixing Banners
题意:
每个测试用例给定6个字符串,看能否用这6个字符串各取1个字符组成“harbin”

思路:
1.深度优先搜索

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
#include<bits/stdc++.h>
using namespace std;
int vis[10][10];
int v[10];

bool dfs(int step)
{
if(step == 6)
return 1;
for(int i = 0; i < 6; i++)
{
if(vis[i][step] && !v[i])
{
v[i] = 1;
if(dfs(step+1))
return 1;
v[i] = 0;
}
}
return 0;
}

int main()
{
int t;
cin >> t;
while(t--)
{
string s[7];
for(int i = 0; i < 6; i++)
cin >> s[i];
memset(vis,0,sizeof(vis));
memset(v,0,sizeof(v));
for(int i = 0; i < 6; i++)
{
for(int j = 0; j < s[i].size(); i++)
{
if(s[i][j] == 'h')
vis[i][0] = 1;
else if(s[i][j] == 'a')
vis[i][1] = 1;
else if(s[i][j] == 'r')
vis[i][2] = 1;
else if(s[i][j] == 'b')
vis[i][3] = 1;
else if(s[i][j] == 'i')
vis[i][4] = 1;
else if(s[i][j] == 'n')
vis[i][5] = 1;
}
}
if(dfs(0))
cout << "Yes" << endl;
else cout << "No" << endl;
}
return 0;
}
  • Copyright: Copyright is owned by the author. For commercial reprints, please contact the author for authorization. For non-commercial reprints, please indicate the source.
  • Copyrights © 2020-2024 Rye
  • Visitors: | Views:

请我喝杯咖啡吧~

支付宝
微信